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Configuration = 125
cycles = (10 8 1 9 6)(7 4 2 5 3)

a = 1, b = 2, c = 5
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cycles = (10 8 4 2 7 3 1 9 6)(5)

a = 2, b = 7, c = 10
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cycles = (10 6 1 4 9)(8)(7 5 3)(2)

a = 1, b = 4, c = 6
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cycles = (10 6 9)(8)(7 2 5)(4)(3)(1)

a = 6, b = 9, c = 10
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cycles = (10)(9)(8 2 5)(7)(6)(4)(3)(1)